The total surface area of a solid right circular cylinder is 660 sq.cm. If its diameter of the base is 14 cm, find the height and curved surface area of the cylinder.
Given : Total surface area (TSA) of cylinder = 660 sq.cm.
Diameter of the base of the cylinder = d = 14 cm
To find : Height of cylinder = h = ?
Curved surface area (CSA) of cylinder = ?
Formula : d = 2r
TSA of cylinder = 2πr (h + r)
CSA of cylinder = 2πrh
Solution : diameter = d = 2r
⇒ Radius = r =
=
= 7 cm
TSA of cylinder = 2
r (h + r)
⇒ 660 = 2 ×
× 7 (h + 7)
660 = 44 (h + 7)
44 (h + 7) = 660
⇒ h + 7 = ![]()
h + 7 = 15
⇒ h = 15 – 7
h = 8 cm
CSA of cylinder = 2
rh = 2 ×
× 7 × 8
= 44 × 8 = 352 cm2
∴ The height of the right circular cylinder is 8 cm and its curved surface area is 352 cm2.
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