In the given figure, LM || CB and LN || CD Prove that 

Given, LM||CB and LN||CD
Need to prove ![]()
⇒ In
ACB, LM || CB
⇒ now, we know that line drawn parallel to one side of the triangle, intersects the other two sides in distinct points, then it divides the other 2 side in same ratio.
∴
……….eq(1)
And in
ACD, LN||CD
⇒
…………eq(2)
From eq(1) and eq(2), we get
⇒ ![]()
⇒ ![]()
Adding 1 on both sides we get
⇒
+ 1 =
+ 1
⇒
= ![]()
⇒
= ![]()
⇒
= ![]()
Hence, proved.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.




