Q6 of 42 Page 210

AB, CD, PQ are perpendicular to BD. AB = x, CD = y and PQ = z prove that

Given, in Δ BCD, PQ || CD


….eq(1)


And in Δ ABD, PQ||AB


⇒ ….eq(2)


Need to prove that


⇒ From eq(1) and eq(2) we have


⇒


⇒ 1- [FROM EQ(1)]


⇒ 1 = PQ()


⇒ …..eq(3)


Since, from the question we know that AB = X CD = Y and PQ = z


Substituting those values in eq(3) we get


⇒


∴


Hence proved


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