Q7 of 42 Page 214

ABC is a triangle and PQ is a straight line meeting AB and P and AC in Q. If AP = 1 cm. and BP = 3 cm, AQ = 1.5 cm., CQ = 4.5 cm.

Prove that


(area of ΔAPQ)

Given, AP = 1cm, BP = 3cm and AQ = 1.5cm,CQ = 4.5cm


Need to prove (area of Δ APQ) = area of Δ ABC



⇒ it is evident that Δ ABC ∼ Δ APQ we know that


⇒ =


= =


⇒ Area of Δ APQ = Area of Δ ABC


Hence proved


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