Q11 of 42 Page 210

Construct a triangle of sides 4 cm, 5 cm and 6 cm. Then, construct a triangle similar to it, whose sides are of the corresponding sides of the first triangle.


Given, sides AB = 4cm, BC = 5cm, CA = 6cm.


Need to construct a triangle whose sides are of the corresponding sides of Δ ABC.


Construction steps:


1) Making an angle of 30° draw any ray BX with the base BC of Δ ABC on the opposite side of the vertex A


2) Locate three points B1,B2,B3 on BX so that BB1 = BB2 = BB3, the number of points should be greater of m and n in the scale factor


3) Join B2 to C’ and draw a line through B3 parallel to B2C intersecting the line segment BC at C.


4) Draw a line through C parallel to C’A intersecting the line segment BA at A’. Then A’B’C is the required triangle.


Hence proved


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