Prove that the area of the equilateral triangle described on the side of a square is half the area of the equilateral triangles described on its diagonal.
Need to prove that the area of the equilateral triangle described on the side of a square is half the area of the equilateral triangles described on its diagonal
⇒ Let us take a square with side ‘a’
⇒ Then the diagonal of square will be a√ 2
⇒ Area of equilateral triangle with side ‘a’ is ![]()
⇒ Area of equilateral triangle with side a√2 is ![]()
⇒ Ratio of two areas can be given as follows
⇒ 
Hence proved
Couldn't generate an explanation.
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