Q1 of 26 Page 49

What is the sum of the angles of a 52-sided polygon?

Given: Number of sides of polygon = 52

Sum of the angles of n-sided polygon = (n – 2) × 180°


⇒ S = (52 – 2) × 180°


⇒ S = 50 × 180°


⇒ S = 9000


∴ The sum of the angles of 52-sided polygon is 9000°.


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The sum of the angles of a polygon is 8100°. How many sides does it have?

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All the angles of a 20-sided polygon are the same. How much is each?

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The sum of the angles of a polygon is 1980°. What is the sum of the angles of a polygon with one side less? What about a polygon with one side more?