The sum of the angles of a polygon is 1980°. What is the sum of the angles of a polygon with one side less? What about a polygon with one side more?
Given: Sum of the angles = 1980°
Sum of the angles of n-sided polygon = (n – 2) × 180°
⇒ 1980° = (n – 2) × 180°
⇒ ![]()
⇒ 11 = n – 2
⇒ n = 11 + 2
⇒ n = 13
∴ The number of sides of polygon having sum of the angles of 1980° is 13 sides.
When the number of sides of polygon one side less than 13-sided polygon.
Number of sides of polygon = 12
Sum of the angles of n-sided polygon = (n – 2) × 180°
⇒ S = (12 – 2) × 180°
⇒ S = 10 × 180°
⇒ S = 1800
∴ The sum of the angles of 12-sided polygon is 1800°.
When the number of sides of polygon one side more than 13-sided polygon.
Number of sides of polygon = 14
Sum of the angles of n-sided polygon = (n – 2) × 180°
⇒ S = (14 – 2) × 180°
⇒ S = 12 × 180°
⇒ S = 2160
∴ The sum of the angles of 14-sided polygon is 2160°.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
