Compute all angles of each of the figures below:

Let us name the vertices of quadrilateral

∠ ADC + ∠ ADE = 180° (linear pair of angles at a vertex)
⇒ ∠ ADC + 80° = 180°
⇒ ∠ ADC = 180° - 80°
⇒ ∠ ADC = 100°
∠ DCB + ∠ DCJ = 180° (linear pair of angles at a vertex)
⇒ ∠ DCB + 95° = 180°
⇒ ∠ DCB = 180° - 95°
⇒ ∠ DCB = 85°
Sum of the angles of 4-sided polygon
Sum of the angles of n-sided polygon = (n – 2) × 180°
⇒ S = (4 – 2) × 180°
⇒ S = 2 × 180°
⇒ S = 360°
In ABCD
∠ A + ∠ B + ∠ C + ∠ D = 360°
⇒ ∠ A + 85° + 85° + 100° = 360°
⇒ 270° + ∠ A = 360°
⇒ ∠ A = 360° - 270°
⇒ ∠ A = 90°
∠ BAG + ∠ BAD = 180°
⇒ ∠ BAG + 90° = 180°
⇒ ∠ BAG = 180° - 90°
⇒ ∠ BAG = 90°
∠ BAG = ∠ DAF (opposite angle at a vertex)
∠ DAF = 90°
∠ DAB = ∠ GAF (opposite angle at a vertex)
∠ GAF = 90°
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

