The figure shown a regular pentagon and a regular hexagon put together. How much is ∠PQR?

In regular pentagon,
Sum of the angles of n-sided polygon = (n – 2) × 180°
⇒ S = (5 – 2) × 180°
⇒ S = 3 × 180°
⇒ S = 540°
Measure of each interior angle ![]()
⇒ ![]()
In regular hexagon,
Sum of the angles of n-sided polygon = (n – 2) × 180°
⇒ S = (6 – 2) × 180°
⇒ S = 4 × 180°
⇒ S = 720°
Measure of each interior angle ![]()
⇒ ![]()
Let us assume the point opposite to Q as S.

∠ PQS + ∠ RQS + ∠ PQR = 360° (pair of angles at a vertex)
⇒ 120° + 108° + ∠ PQR = 360°
⇒ 228° + ∠ PQR = 360°
⇒ ∠ PQR = 360° - 228°
⇒ ∠ PQR = 132°
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