Compute all angles of each of the figures below:

Let us name the vertices of quadrilateral.

∠ CDA + ∠ CDE = 180° (linear pair of angles at a vertex)
⇒ ∠ CDA + 115° = 180°
⇒ ∠ CDA = 180° - 115°
⇒ ∠ CDA = 65°
Sum of the angles of 4-sided polygon
Sum of the angles of n-sided polygon = (n – 2) × 180°
⇒ S = (4 – 2) × 180°
⇒ S = 2 × 180°
⇒ S = 360°
In ABCD
∠ A + ∠ B + ∠ C + ∠ D = 360°
⇒ ∠ A + 100° + 75° + 65° = 360°
⇒ 240° + ∠ A = 360°
⇒ ∠ A = 360° - 240°
⇒ ∠ A = 120°
∠ DAH + ∠ DAB = 180° (linear pair of angles at a vertex)
⇒ ∠ DAH + 120° = 180°
⇒ ∠ DAH = 180° - 120°
⇒ ∠ DAH = 60°
∠ ABG + ∠ ABC = 180° (linear pair of angles at a vertex)
⇒ ∠ ABG + 100° = 180°
⇒ ∠ ABG = 180° - 100°
⇒ ∠ ABG = 80°
∠ BCF + ∠ BCD = 180° (linear pair of angles at a vertex)
⇒ ∠ BCF + 75° = 180°
⇒ ∠ BCF = 180° - 75°
⇒ ∠ BCF = 105°
Couldn't generate an explanation.
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