Q3 of 113 Page 128

In Fig. 5.9, PQ is a mirror, AB is the incident ray and BC is the reflected ray. If ∠ABC = 46°, then ∠ABP is equal to

Angle of incidence(i) = Angle of reflection(r)


∠ABC = Angle of incidence(i) + Angle of reflection(r)


∠ABC = 46° (Given)


⇒ 2i = 46°


⇒ i = 23°


∠ABP + i = 90°


⇒ ∠ABP = 67°

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