Three lines AB, CD and EF intersect each other at O. If ∠AOE = 30° and ∠DOB = 40° (Fig. 5.51), find ∠COF.

∠AOE, ∠DOB and ∠ EOD forms a linear pair
∠AOE = 30°
∠DOB = 40°
∠ EOD = 1800-∠AOE- ∠DOB
⇒ ∠ EOD = 1100
∠COF = ∠ EOD = 1100( Vertically Opposite)
∠COF = 1100
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

