In Fig. 5.11, if AB || CD, ∠APQ = 50° and ∠PRD = 130°, then ∠QPR is

∠APQ = 50°(Given)
⇒ ∠PQR = 50°(Alternate interior angles)
∠PRD = 130°(Given)
∠PRD = (180°- 130°) = 50° (Forms a Linear pair)
Sum of interior angles of a triangle = 180°
∠ QPR = 180°- ∠PQR-∠PRD
∠ QPR = 180°-100°
∠ QPR = 80°
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