In Fig. 5.53, find the value of ∠BOC, if points A, O and B are collinear.

∠ AOD, ∠ DOC and ∠ COB are linear pairs.
So the sum of this three angles is 1800
(x-10) + (4x-25) + (x + 5) = 180
⇒ 6x = 180 + 30
⇒ 6x = 210
⇒ x = 350
∠BOC = (x + 5)0 = 400
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