In Fig. 5.64, find out which pair of lines are parallel:


∠ VUF + ∠ TUV = 1800
∠ TUV = 1800-1230 = 570
∠ TUV = ∠UVH
So they form alternate interior pairs
Hence EF||GH
∠UVH≠∠ VQP
Hence PK is not parallel to EF and GH
∠ VUF≠∠RSV
Hence AB is not parallel to CD as they don’t form corresponding pairs.
EF||GH
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