In Fig. 5.65, show that

(i) AB || CD
(ii) EF || GH

Let P,Q,R,S be the four intersecting point
∠ FQS and ∠ SQP forms a linear pair
∠ SQP = 1800-500 = 1300
∠ APQ = 1300
∠ APQ = ∠ SQP = 1300
∠ APQ & ∠ SPQ are alternate interior angles
Hence AB || CD
∠ APQ and ∠ QPR forms a linear pair
∠ QPR = 1800-1300 = 500
∠ QPR = ∠ GRP = 500
So ∠ QPR and ∠ GRP are alternate interior angles
Hence EF || GH
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