In Fig. 5.49, AB||CD, AF||ED, ∠AFC = 68° and ∠FED = 42°. Find ∠EFD.

∠FED = ∠AFE = 42° (Alternate interior angle)
∠AFC, ∠AFE and ∠EFD are supplementary
∠EFD = 1800-(680 + 420) = 700
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