Obtain the value of the following polynomials at the given values of x:

(1) p(x) = 2x³ + 3x² + 7x + 9 ; at x = 0, 1

(2) p(x) = 3x² + 10x + 7 ; at x = —3, 1

(3) p(x) = x² — 2x + 5 ; at x = —1, 5

(4) p(x) = 2x⁴ — 3x³ + 7x + 5 ; at x = —2, 2

(1) Given, p(x) = 2x³ + 3x² + 7x + 9

p(0) = 2(0)³ + 3(0)² + 7(0) + 9

p(0) = 0 + 0 + 9 = 9

p(1) = 2(1)³ + 3(1)² + 7(1) + 9

p(1) = 2 + 3 + 7 + 9 = 21

(2) Given, p(x) = 3x² + 10x + 7

p(–3) = 3(–3)² + 10(–3) + 7

p(–3) = 27 – 30 + 7 = 4

p(1) = 3(1)² + 10(1) + 7

p(1) = 3 + 10 + 7 = 20

(3) Given, p(x) = x² — 2x + 5

p(–1) = (–1)² – 2(–1) + 5

p(–1) = 1 + 2 + 5 = 8

p(5) = (5)² – 2(5) + 5

p(5) = 25 – 10 + 5 = 20

(4) Given, p(x) = 2x⁴ — 3x³ + 7x + 5

p(–2) = 2(–2)⁴ – 3(–2)³ + 7(–2) + 5

p(–2) = 32 + 24 – 14 + 5 = 47

p(2) = 2(2)⁴ – 3(2)³ + 7(2) + 5

p(2) = 32– 24 + 14 + 5 = 27