Obtain a quadratic polynomial with the following conditions:
The sum of zeros = 2; the product of zeros = —3
Let α and β be the zeros of the polynomial p(x) = ax2 + bx + c.
Given, α + β = 2 ; αβ = –3
We know that α + β = –
= –
. So, –
=
= k, say
Thus, b = –2k, a = k
And αβ =
= –
. So, c = –3a = –3(k) = –3k
p(x) = ax2 + bx + c
∴ p(x) = (k)x2 + (–2k)x – 3k
∴ p(x) = k (x2 – 2x – 3)
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