Prove that the points (1, –2), (3, 0), (1, 2) and (–1, 0) are the vertices of a square.
We have A → (1, –2)

B → (3, 0)
C → (1, 2)
D → (–1, 0)
Using the distance formula,
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We find that AB = BC = CD = DA.
⇒ ABCD is a square.
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