Q10 of 48 Page 99

Prove that the points (1, 1) (–2, 7) and (3, –3) are collinear.

We have A → (1, 1)


B → (–2, 7)


C → (3, –3)


Using the distance formula,














We find that,


AB + BC = 3√5 + 2√5 = 5√5 = CA


⇒ The points A, B and C are collinear.


More from this chapter

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8

Prove that the points (1, –2), (3, 0), (1, 2) and (–1, 0) are the vertices of a square.

 9

Prove that the points (a, a), (–a, –a) and are the vertices of an equilateral triangle.

11

Find the points on x-axis which are situated at equal distances from the points (–2, –5) and (2, –3).

 12

Find the points on y-axis which are situated at equal distances from the points (–5, –2) and (3, 2).