The triangle with vertices (–2, 1), (2, –2) and (5, 2) is :
We have A → (–2, 1)
B → (2, –2)
C → (5, 2)
Using the distance formula,
AB = 
=
=
=
= 5
BC = 
=
=
=
CA = 
=
=
=
We find that (AB)2 + (CA)2 = (BC)2, or simply (5, 5, √50) forms a pythagorean triplet and hence the points A, B and C form a right angled triangle.
∴ The correct option is A.
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