We have A → (a, a)
B → (–a, –a)
C → (
)
Using the distance formula,
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We know that (a – b)2 + (a + b)2 = (a2 + b2 – 2 ab) + (a2 + b2 + 2 ab) = 2(a2 + b2 )
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We find that AB = BC = CA.
⇒ Points A, B and C form an equilateral triangle.
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