Q11 of 48 Page 99

Find the points on x-axis which are situated at equal distances from the points (–2, –5) and (2, –3).

We have A → (–2, –5)


B → (x, 0) equidistant from A and C


(y = 0 since B lies on X-axis)


C → (2, –3)


Using the distance formula,









Since B is equidistant from A and C


∴ AB = BC



Squaring both sides



8x + 16 = 0


x = –2


The required point is B (–2, 0).


More from this chapter

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9

Prove that the points (a, a), (–a, –a) and are the vertices of an equilateral triangle.

10

Prove that the points (1, 1) (–2, 7) and (3, –3) are collinear.

 12

Find the points on y-axis which are situated at equal distances from the points (–5, –2) and (3, 2).

 13

If the distances of the point (0, 2) from the points (3, k) and (k, 5) are equal then find the value of k.