Solve the following:
(i) x + 3 = 11 (ii) y - 9 = 21
(iii) 10 = z + 3 (iv) 
(v) 10x = 30 (v) 10x = 30
(vi)
(vii) 
(viii)
(ix) 8x – 8 = 48
(x)
(xi) 
(xii)
(xiii) 3(x + 6) = 24
(xiv)
(xv) 3(x + 2) – 2(x – 1) = 7
Note: - Our Main Motto is to bring variable to one side of the equation and find the value
(i) x + 3 = 11
Taking 3 to right side of equation,
⇒ x = 11 - 3 = 8
x = 8
(ii) y - 9 = 21
Taking 9 to the right side of equation,
⇒ y = 21 + 9 = 30
y = 30
(iii) 10 = z + 3
Bring 3 to left side of equation,
⇒ z = 10 - 3 = 7
z = 7
(iv) 
⇒ ![]()
![]()
(v) 10x = 30
Take 10 to right hand side of the equation,
⇒ ![]()
x = 3
(vi) 
Take 7 to right hand side of equation,
⇒ s = 7 × 4
s = 28
(vii) 
⇒![]()
Taking 2 to right side of equation,
⇒ x = 10 × 2
x = 20
(viii) 
Take 1.5 to left side of equation,
⇒ x = 1.6 × 1.5
x = 2.4
(ix) 8x – 8 = 48
⇒ 8x = 48 + 8
⇒8x = 56
⇒ x = (56/8) = 7
x = 7
(x) 
⇒ ![]()
⇒ ![]()
⇒ x = - 8/5
(xi) 
⇒ x = 5 × 12 = 60
x = 60
(xii) 
⇒ 3x = 15 × 5
⇒ x = (15 × 5)/3
⇒ x = 5 × 5 = 25
x = 25
(xiii) 3(x + 6) = 24
⇒ ![]()
⇒ x + 6 = 8
⇒ x = 8 - 6 = 2
x = 2
(xiv) 
![]()
![]()
⇒ x = 9 × 4 = 36
x = 36
(xv) 3(x + 2) – 2(x – 1) = 7
Expanding the expressing we get,
3x + 6 - 2x + 2 = 7
Place Variable in one side and numbers in the other side of equation,
⇒ 3x - 2x = 7 - 6 - 2
⇒ x = - 1
x = - 1
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