Q1 of 46 Page 152

Solve the following:

(i) x + 3 = 11 (ii) y - 9 = 21


(iii) 10 = z + 3 (iv)


(v) 10x = 30 (v) 10x = 30


(vi) (vii)


(viii) (ix) 8x – 8 = 48


(x) (xi)


(xii) (xiii) 3(x + 6) = 24


(xiv) (xv) 3(x + 2) – 2(x – 1) = 7

Note: - Our Main Motto is to bring variable to one side of the equation and find the value


(i) x + 3 = 11


Taking 3 to right side of equation,


x = 11 - 3 = 8


x = 8


(ii) y - 9 = 21


Taking 9 to the right side of equation,


y = 21 + 9 = 30


y = 30


(iii) 10 = z + 3


Bring 3 to left side of equation,


z = 10 - 3 = 7


z = 7


(iv)




(v) 10x = 30


Take 10 to right hand side of the equation,



x = 3


(vi)


Take 7 to right hand side of equation,


s = 7 × 4


s = 28


(vii)



Taking 2 to right side of equation,


x = 10 × 2


x = 20


(viii)


Take 1.5 to left side of equation,


x = 1.6 × 1.5


x = 2.4


(ix) 8x – 8 = 48


8x = 48 + 8


8x = 56


x = (56/8) = 7


x = 7


(x)




x = - 8/5


(xi)


x = 5 × 12 = 60


x = 60


(xii)


3x = 15 × 5


x = (15 × 5)/3


x = 5 × 5 = 25


x = 25


(xiii) 3(x + 6) = 24



x + 6 = 8


x = 8 - 6 = 2


x = 2


(xiv)




x = 9 × 4 = 36


x = 36


(xv) 3(x + 2) – 2(x – 1) = 7


Expanding the expressing we get,


3x + 6 - 2x + 2 = 7


Place Variable in one side and numbers in the other side of equation,


3x - 2x = 7 - 6 - 2


x = - 1


x = - 1


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