The digit at the tens place of a two digit number is three times the digit at the units’ place. If the sum of this number and the number formed by reversing its digit is 88, find the number.
Let, the digit at unit’s place = x
∴ digit at ten’s place = 3x
∴ The two digit number = 10 × 3x + x = 31x
After reversing the digits,
Digit at unit’s place = 3x
Digit at ten’s place = x
∴ Number formed after reversing the digits = 10 × x + 3x = 13x
According to problem,
⇒ 31x + 13x = 88
⇒ 44x = 88
⇒ x = 2
∴ The two digit number = 31 × 2 = 62
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