Evaluate the following Integrals:
Let 
Put 1 + log x = t
(Differentiating both sides)
When x = 1, t = 1 + log 1 = 1
When x = 2, t = 1 + log 2
So, the new limits are 1 and 1 + log 2.
Substituting this in the original integral,
Recall 
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