Evaluate the following integrals as a limit of sums:

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Formula used:
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where,
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Here, a = -1 and b = 1
Therefore,
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Let,
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Here, f(x) = x + 3 and a = -1
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Now, By putting x = -1 in f(x) we get,
f(-1) = -1 + 3 = 2
Similarly, f(-1 + h)
= -1 + h + 3
= h + 2
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In this series, 2 is getting added n times
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Now take h common in remaining series
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Put,
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Since,
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