Evaluate the following Integrals:

![]()
= ![]()
Let’s Say I = I1 + I2
And, I1 = ![]()
Using Integration By parts
![]()
f’ = e–x, g = x
f = –e–x, g’ = 1



I1=![]()
For I2 =
Using Integration By parts
![]()
f’ = ex, g = x
f = ex, g’ = 1



I2=![]()
Now, I = I1 + I2
=
=0
Hence, 0
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