Evaluate the following integral:

Let us assume ![]()

since logmn = logm + logn and log(m)n = nlogm

.......equation (a)
Let ![]()
We know that ![]()
If f(2a – x) = f(x)
than ![]()
thus
………equation 1
since logsin(π – x) = logsinx
By property, we know that ![]()

………equation 2
Adding equation 1 and equation 2
+ ![]()
We know


We know logm + logn = logmn thus


since log(m/n) = logm – logn
.....equation 3
Let ![]()
Let 2x = y
2dx = dy
dx = dy/2
For x = 0
y = 0
for ![]()
y = π
thus substituting value in I1

From equation 3 we get
![]()
![]()
Thus substituting the value of I2 in equation 3


![]()
![]()
![]()
![]()
Substituting in equation (a) i.e


![]()
I = ![]()
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