Evaluate the following integrals as a limit of sums:

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Formula used:
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where,
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Here, a = 3 and b = 5
Therefore,
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Let,
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Here, f(x) = 2 – x and a = 3
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Now, By putting x = 3 in f(x) we get,
f(3) = 2 – 3 = -1
Similarly, f(3 + h)
= 2 – (3 + h)
= 2 – 3 – h
= -1 – h
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In this series, -1 is getting added n times
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Now take -h common in remaining series
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Put,
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Since,
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