Q7 of 35 Page 143

A body of mass 1kg is kept at rest. A constant force of 6N starts acting on it. Find the time taken by the body to move through a distance of 12m?


Force = Mass × Acceleration


6N = 1kg × a


6m/s2 = a


Using Second equation of motion


s = ut + 1/2at2


12 = 0(t) + 1/2* (6)* t2


12 = 3t2


4 = t2


t = √4


= +2 or –2 ; as time can’t be negative so, positive value of time is taken.


2s = t


Therefore, time taken is 2s.


More from this chapter

All 35 →
5

Give two examples to show that greater the mass greater is the inertia of the body?

 6

A scooter of mass 120kg is moving with a uniform velocity of 108km/hr. Find out the force required to stop the vehicle in 10s?

 8

A constant force acts on an object of mass 5kg for a duration of 2s. It increases the object velocity from 3m/s to 7m/s. Find the magnitude of the force applied. Now if the force were applied for a duration of 5s, what would be the final velocity of the object?

 9

A car of mass 2kg is at rest. What should be the magnitude of force which will make the body move with a speed of 30m/s at the end of 1s?