Q12 of 35 Page 143

When a horizontal force P acts on a cart of mass 20 kg it moves with a uniform velocity on a horizontal floor. When a force of 1.2P acts on the cart it moves with an acceleration of 0.05 metre per second square. Find the value of P.

Friction inhibits the movement of the cart.

Let friction be F and force is P.


As the velocity is zero.


F – P = 0


F = P


Force acting is 1.2 P on cart,


For Acceleration, a: 1.2P – F = ma


1.2P – P = 20kg ×0.05m/s2


0.2P = 20kg × 0.05m/s2


P = 5N


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