Evaluate: 
Let, I = ![]()
Putting ![]()
![]()
When, x = 0, ![]()
![]()
x = 2, ![]()
![]()
I = ![]()
= 2 ![]()
= 2
{∵ 2cos2θ = 1 + cos 2θ}
= 2 ![]()
= 2 ![]()
= 2 [π/2]
= ![]()
The required value is π.
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