Find the distance of the plane 3x – 4y + 12z = 3 from the origin.
Coordinates of origin = (0,0,0)
We know that, perpendicular distance of a point (x1,y1,z1) from a plane ax + by + cz + d = 0 is given by-

∴ Perpendicular Distance of plane 3x – 4y + 12z -3 =0 from origin (0, 0, 0) is = ![]()
p = ![]()
p = ![]()
p = ![]()
The perpendicular distance is
units.
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