A ladder 5 m long is leaning against a wall. The bottom of the ladder is pulled along the ground, away from the wall, at the rate of 2 cm/s. How fast is its height on the wall decreasing when the foot of the ladder is 4 m away from the wall?

As per the Pythagoras Theorem,
![]()
∴ In right angled triangle - Δ ABC we have –
x2 + y2 = 52
Differentiating w.r.t t both sides -
![]()
⇒ ![]()
⇒ ![]()
When, x = 4 m
y2 = 25 – 16 = 9
∴ y = 3
Given,
= 2 m/sec
∴
cm/sec
The height of the ladder on the wall is decreasing at the rate of
cm/sec.
Couldn't generate an explanation.
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