If the lines
and
are perpendicular, find the value of k and hence find the equation of the plane containing these lines.
Given equations are –
L1: ![]()
It can also be represented in vector form.
∴ L1: ![]()
And L2: ![]()
It can also be represented in vector form.
∴ L2: ![]()
For lines to be perpendicular, the dot product of their direction vectors must be zero.
∴ ![]()
⇒ -3k – 2k + 10 = 0
⇒ -5k = -10
∴ k = 2
∴ equation of line can be rewritten as –
L1: ![]()
And L2: ![]()
Equation of plane containing the lines is given by -
= 0
⇒ (x – 1) (-20 – 2) – (y – 2) (-15 – 4) + (z – 3) (-3 + 8) = 0
⇒ -22x + 19y + 5z = 31
Required equation of the plane is: -22x + 19y + 5z = 31
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