If
find (x, y)
Given:
⇒ ![]()
Rationalising denominator
⇒ ![]()
⇒ ![]()
We know that i2=-1
⇒ 
⇒ ![]()
⇒ ![]()
⇒ i3–(-i)3=x+iy
⇒ 2i3=x+iy
⇒ 2i2.i=x+iy
⇒ 2(-1)i=x+iy
⇒ -2i=x+iy
Equating Real and Imaginary parts on both sides we get
⇒ x=0 and y=-2
∴ The values of x and y are 0 and -2.
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