Evaluate the following :
x6 + x4 + x2 + 1, when
.
Given:
⇒ ![]()
⇒ x6+x4+x2+1
⇒ x4(x2+1)+1(x2+1)
⇒ (x4+1)(x2+1)
⇒ ![]()
⇒ 
⇒ 
We know that i2=-1
⇒ 
⇒ ![]()
⇒ (-1+1)(i+1)
⇒ (0)(i+1)
⇒ 0
∴ x6+x4+x2+1=0
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