If
is purely imaginary number (z ≠ – 1), find the value of |z|.
Given:
⇒
is purely imaginary
⇒ Let us assume
, where K is any real number
Let us assume z=x+iy
⇒ ![]()
Multiplying and dividing with (x+1)-iy
⇒ ![]()
⇒ 
⇒ ![]()
We know that i2=-1
⇒ ![]()
⇒ ![]()
Equating Real and Imaginary parts on both sides we get
⇒ ![]()
⇒ x2+y2-1=0
⇒ x2+y2=1
⇒ ![]()
⇒ |z|=1
∴ |z|=1
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