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13. Complex Numbers
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Q26 of 153 Page 13

Find the number of solutions of z2 + |z|2 = 0.

Given:


⇒ z2+|z|2=0


Let us assume z=x+iy


⇒


⇒ x2+(iy)2+2(x)(iy)+x2+y2=0


⇒ 2x2+y2+i2y2+i2xy=0


We know that i2=-1


⇒ 2x2+y2-y2+i2xy=0


⇒ 2x2+i2xy=0


Equating Real and Imaginary parts on both sides we get,


⇒ 2x2=0 and 2xy=0


⇒ x=0 and yR


∴ z=0+iy where yR. i.e, Infinite solutions.


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Questions · 153
13. Complex Numbers
1 2 3 3 3 3 3 3 3 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 3 3 3 3 3 3 4 4 4 4 5 6 7 8 9 10 11 12 13 14 15 16 16 16 16 16 17 18 19 20 21 22 23 24 25 26 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 3 3 3 3 4 5 6 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43
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