Express the following complex numbers in the form ![]()
1 + i tan α
Given Complex number is Z=1+itanα
We know that the polar form of a complex number Z=x+iy is given by Z=|Z|(cosθ+isinθ)
Where,
|Z|=modulus of complex number=![]()
θ =arg(z)=argument of complex number=![]()
We know that tanα is a periodic function with period
.
We have
lying in the interval ![]()
Case1:
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
Since sec
is positive in the interval ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
Since tan
is positive in the interval ![]()
⇒ θ=![]()
∴ The polar form is z=sec
(cos
+isin
).
Case2:
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
Since sec
is negative in the interval
.
⇒ ![]()
⇒ ![]()
⇒ ![]()
Since tan
is negative in the interval
.
⇒
.(∵ θ lies in 4th quadrant)
⇒ z=-sec
(cos(
)+isin(
))
⇒ z=-sec
(-cos
-isin
)
⇒ z=sec
(cos
+isin
)
∴ The polar form is z=sec
(cos
+isin
)
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