If
then show that ![]()
Given:
⇒ (1+i)z=(1-i)![]()
Dividing with (1+i) on both sides we get,
⇒ ![]()
⇒ ![]()
⇒ ![]()
We know that i2=-1
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ z=-i![]()
∴ Thus proved
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