Find the particular solution, satisfying the given condition, for the following differential equation:
y = 0 when x = 1
Given differential equation is
![]()
This is a homogenous differential equation,
Put ![]()
⇒ y = vx
![]()
∴ we have
![]()
![]()
![]()
⇒ log x = - (- cos v) + C
⇒ log x = cos v + C
![]()
Now, y = 0, when x = 1
![]()
⇒ 0 = - 1 + C
⇒ C = -1
Hence, particular solution is
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.




