Find the volume of the largest cylinder that can be inscribed in a sphere of radius r.
OR
A tank with rectangular base and rectangular sides, open at the top is to be constructed sothat its depth is 2 m and volume is 8 m3. If building of tank costs Rs. 70 per sq. metre for thebase and Rs. 45 per sq. metre for sides, what is the cost of least expensive tank?

Let a right circular cylinder of radius “R” and height “H” is inscribed in the sphere of given radius “r”.
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Let V be the volume of the cylinder.
Then, V = πR2H
…. (1)
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Differentiating both sides w.r.t H to get,
….. (2)
For maximum value put dV/dH = 0
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Again, differentiating w.r.t H we get,
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At
,
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So, volume is maximum when height of cylinder is
.
Substitute
in (1) to get,
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OR
Let the length and breadth of the tank are L and B.
∴ V = 8
2LB = 8
…. (1)
Total surface area S = Area of base + Area of 4 walls
= LB + 2(B+L).2
= LB+4B+4L
The cost of constructing the tank is:
C = 70(LB) + 45(4B + 4L)
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….. (2)
Differentiating both sides w.r.t L we get,
…. (3)
For minimization dC/dL = 0,
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⇒ L2 = 4
⇒ L = 2
Differentiate (3) w.r.t L to get,
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∴ Cost is minimum when L = 2.
From (1),
B = 2
From (2),
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= 280 + 720
= Rs 1000
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