Using the properties of determinants, prove the following:

L.H.S =
C1→ C1 + C2 + C3

take (a + b + c) common from C1.

R3→ R3 - 2R1

= (a + b + c)[(b-c)(a+b-2c)-(c-a)(c+a-2b)]
= a3 +b3 +c3 -3abc
= RHS
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