A die is thrown again and again until three sixes are obtained. Find the probability of obtaining the third six in the sixth throw of the die.
If third 6 has to be in the sixth throw, then first two sixes will be in first 5 throws.
Hence, n = 5
![]()
P (2 sixes) = 5C2 p2 q3
![]()
![]()
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.



