Differentiate the following function w.r.t. x:
y = (sin x) x + sin-1√x.
formula: -
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given: -
y = (sin x)x +sin-1√x.
v = sin-1√x.
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let u = (sin x) x
taking log both sides
log u = log (sin x) x
⇒ log u = x log sin x
Diff. w.r.t x
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Adding both v and u
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