Using properties of determinants, prove the following:


R1→R1 + bR3



taking common (1 + a2+ b2)

R2→R2 – aR3



Taking common (1 + a2+ b2)

= (1+a2+b2 )2 (1- a2-b2 +2a2+2a2)
= (1+a2+b2 )2 (1+a2+b2 )
= (1+a2+b2 )3
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